The Squeeze Theorem THE LIMIT OF (SINX)/X AS X APPROACHES ZERO #rolandoasisten || CALCULUS | VIDEO NO 92 In this video, we discussed the proof of the limit of sinx/x as x approaches zero using the squeeze/Sandwich theorem. This lesson is a prerequisite in order to find the derivative of the sine function. | Asisten and German Academy
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✅⬇️ The limit of sin(x)/x as x approaches 0 is equal to 1, and this is a fundamental result in calculus. It's often used in various mathematical derivations and proofs. One way to understand this limit is by looking at the behavior of the sine function and the x-axis as x gets closer to 0. The graph of y = sin(x)/x approaches 1 as x approaches 0 because the sine function oscillates between -1 and 1, but the x in the denominator gets smaller, causing the fraction sin(x)/x to approach 1. Another w
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